Keelaparasalur Veerateswarar Temple - temple in India. Article "கீழப்பரசலூர் வீரட்டேசுவரர் கோயில்" in Tamil Wikipedia has 11.5 points for quality (as of July 1, 2025). The article contains 0 references and 5 sections.
Since the creation of article "கீழப்பரசலூர் வீரட்டேசுவரர் கோயில்", its content was written by 12 registered users of Tamil Wikipedia and edited by 12 registered Wikipedia users in all languages.
Keelaparasalur Veerateswarar Temple is on the 508th place in local ranking of buildings on Tamil Wikipedia in all the time.
The article is cited 138 times in Tamil Wikipedia and cited 138 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Tamil: #7019 08.2024 |
Global: #2884882 08.2024 |
On 12 August 2025 in multilingual Wikipedia, Internet users most often read articles on the following topics: Cristiano Ronaldo, Wednesday, Georgina Rodríguez, ChatGPT, Weapons, Jenna Ortega, deaths in 2025, Taylor Swift, Miguel Uribe Turbay, 2025–26 UEFA Champions League.
In Tamil Wikipedia the most popular articles on that day were: விநாயகர் அகவல், வ. உ. சிதம்பரம்பிள்ளை, சுபாஷ் சந்திர போஸ், சுப்பிரமணிய பாரதி, வேலு நாச்சியார், இந்தியாவின் விடுதலை நாள், காமராசர், தமிழ்த் திரைப்படங்களின் பட்டியல் (ஆண்டு வரிசை), கலைஞர் மகளிர் உரிமைத் திட்டம், திருப்பூர் குமரன்.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(9.78+0+20+27.78+0)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
